How much will $5,000 be worth in 10 years?

How quickly $5,000 grows

At 7%, 10 years is not long enough to double $5,000: the balance ends at 1.97 times the original amount. Left alone, it would pass $10,000 during year 11. The rate matters a lot here: the money doubles in year 8 at 10%, while at 4% it would take until year 18, after this 10-year period ends.

Growth also speeds up over time. In year 1 the investment earns $350 at 7%. In year 10 it earns $643, because each year's return is calculated on a larger balance.

What if you change the plan?

Each row changes one thing and keeps everything else the same, at the 7% example rate. The comparison is with $5,000 invested for 10 years, which ends at $9,836.

Waiting 5 years to invest the same $5,000 leaves the final balance $2,823 lower, even though you put in exactly the same amount. The last 5 years add the most because they are earned on the largest balance. A return that is one point lower leaves you with $882 less after 10 years, which is roughly what a 1% annual fee would cost.

Working backwards: to have $25,000 in 10 years at 7% without adding anything, you would need to invest about $12,709 today.

When would the balance reach $25,000?

The table shows the year in which the balance first reaches each amount, assuming nothing is added or withdrawn. Years in bold fall within this page's 10-year period.

How this is calculated

For a single investment with nothing added, the rate is applied once a year to the whole balance:

Balance = Principal × (1 + annual rate)^years

With this page's numbers at 7%:

Balance = 5,000 × 1.07¹⁰ ≈ 5,000 × 1.9672 ≈ $9,836

Growth is the balance minus the original $5,000: $4,836. Every other row in the rate table uses the same formula with a different annual rate. The compound interest calculator page explains the formulas in more detail, including monthly contributions.